优化下面算法x=27eps=0001step=eps2numGuesses=0ans=5whileabsans2-x=epsandans=xans+=stepnumGuesses+=1printnumGuessesnumGuessesifabsans2-x=epsprintFailonsquarerootofxelseprintans
#优化 x=27 eps=0.001 numGuesses=0 ans=5 while abs(ans2-x)>=eps and ans<=x: ans=ans+(x-ans2)/(2*ans) numGuesses+=1 print(’numGuesses:’,numGuesses) if abs(ans**2-x)>=eps: print (‘Fail on square root of’,x) else: print(ans) 本文地址：https://ai.cveoy.com/post/优化下面算法x=27eps=0